Given that $\frac{1}{3} \lambda_m^\infty (Fe^{3+}) = 68 \ \Omega^{-1} \ cm^{2} \ eq^{-1}$ and $\frac{1}{2} \lambda_m^\infty (SO_4^{2-}) = 80 \ \Omega^{-1} \ cm^{2} \ eq^{-1}$. What will be the value of $\lambda_{eq}^\infty (Fe_2(SO_4)_3)$? ............ $\Omega^{-1} \ cm^2 \ eq^{-1}$

  • A
    $148$
  • B
    $880$
  • C
    $364$
  • D
    $130$

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